an another form of grid/table ?

espace3d · August 21, 2014, 9:48am

hi,

Now, i use this type of grid to make my level :

local gridGame = {} local row = 9 local cell = 14 local rectx = 30 local recty = 30 local gridscaley = 0.35 local gridscalex = 0.35 local space = 2 local spaceleft =40 local spacetop = 20 &nbsp;&nbsp;&nbsp; for i = 1, cell do &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; gridGame[i] = {}; &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; for k = 1, row do &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; gridGame[i][k] = display.newImage("dalle.png") &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; gridGame[i][k].yScale=0.35 &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; gridGame[i][k].xScale=0.35 &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; gridGame[i][k].alpha = 1 &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; gridGame[i][k].x = (k - 1) \* (rectx + space) + spaceleft &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; gridGame[i][k].y = (i - 1) \* (recty + space) + spacetop &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; &nbsp; &nbsp;&nbsp;&nbsp; end end

but in the future i would more personnalize and make this

mytable =&nbsp; {} 0 0 1 0 1 0 1 0 0 1 0 1 end

where each number represent a cell

**0 for a red cell

1 for a green cell**

but my question is how to have a space between each cell with this type of representation ?

with the previous grid, it’s make with

gridGame[i][k].x = (k - 1) \* (rectx + space) + spaceleft gridGame[i][k].y = (i - 1) \* (recty + space) + spacetop

But i don’t know how to make this with this new table ?

thanks

espace3d · August 21, 2014, 2:44pm

anybody ? please

espace3d · August 21, 2014, 3:08pm

i try this but without success

local gridGame = {} local widthscreen =320 local heightscreen =480 local row = 24 local cell = 12 local rectx = 30 local recty = 30 local gridscaley = 0.35 local gridscalex = 0.35 local space = 2 local spaceleft =40 local spacetop = 20 local divx=widthscreen/(row\*2) local divy=heightscreen/(cell\*2) local maze = { &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; { x, x,&nbsp; }, &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; { x, w,&nbsp; }, &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; { x, x,&nbsp; }, &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; { x, w,&nbsp; }, &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; { x, x,&nbsp; }, &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; { x, w,&nbsp; }, &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; { x, w,&nbsp; }, &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; { x, w,&nbsp; }, &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; { x, w,&nbsp; }, &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; { x, w,&nbsp; }, &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; { x, w,&nbsp; }, &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; { x, w,&nbsp; }, &nbsp;&nbsp;&nbsp; } &nbsp;&nbsp;&nbsp; maze.rows = table.getn(maze) &nbsp;&nbsp;&nbsp; maze.columns = table.getn(maze[1]) &nbsp;&nbsp;&nbsp; maze.xStart, maze.yStart = 1, 100 &nbsp;&nbsp;&nbsp; maze.xFinish, maze.yFinish = 24, 7 &nbsp;&nbsp;&nbsp; maze.object = x or w &nbsp;&nbsp;&nbsp;&nbsp; if maze.object == x then &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; image="dalle9.png" &nbsp;&nbsp;&nbsp; end &nbsp;&nbsp;&nbsp; if maze.object == w then &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; image="dalle1.png" &nbsp;&nbsp;&nbsp; end &nbsp; &nbsp; &nbsp;&nbsp;&nbsp; for i = 1, maze.rows do &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; gridGame[i] = {}; &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; for k = 1, maze.columns do &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; gridGame[i][k] = display.newImage(image)&nbsp;&nbsp;&nbsp; &nbsp; &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; gridGame[i][k].yScale=0.35 &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; gridGame[i][k].xScale=0.35 &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; gridGame[i][k].alpha = 1 &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; gridGame[i][k].x = (k - 1) \* (rectx + space) + spaceleft &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; gridGame[i][k].y = (i - 1) \* (recty + space) + spacetop &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; &nbsp; &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; end &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; end

nick_sherman · August 21, 2014, 3:15pm

It’s not really clear what you’re trying to do and what is going wrong…

espace3d · August 21, 2014, 4:48pm

i would simply assign an image to letter x and another image for w.

espace3d · August 21, 2014, 5:54pm

i try an another way but always without success

local widthscreen =320 local heightscreen =480 local space = 2 local rectx = 0.35 local recty = 0.35 local spaceleft =40 local spacetop = 20 local maze = { &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; { 1, 2, 1 }, &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; { 2, 2, 2 }, &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; { 2, 1, 2 }, &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; { 2, 2, 1 }, &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; { 1, 1, 2 }, &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; { 2, 2, 1 }, &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; { 1, 1, 1 }, &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; { 2, 1, 1 }, &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; { 2, 2, 1 }, &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; { 2, 1, 2 }, &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; { 2, 1, 2 }, &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; { 1, 2, 1 }, &nbsp;&nbsp;&nbsp; } &nbsp;&nbsp;&nbsp; maze.rows = table.getn(maze) &nbsp;&nbsp;&nbsp; maze.cells = table.getn(maze[1]) &nbsp;&nbsp; local gridGame = {} &nbsp;&nbsp;&nbsp; for i = 1, maze.rows do &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; gridGame[i] = {}; &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; for k = 1, maze.cells do &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; if gridGame[i][k] == 2 then &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; im = display.newImage("icone.png") &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; end &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; if gridGame[i][k] == 1 then &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; im = display.newImage("bulle2.png") &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; end&nbsp;&nbsp; &nbsp; &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; gridGame[i][k] = im &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; gridGame[i][k].yScale = 0.35 &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; gridGame[i][k].xScale = 0.35 &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; gridGame[i][k].x = (k - 1) \* (rectx + space) + spaceleft &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; gridGame[i][k].y = (i - 1) \* (recty + space) + spacetop &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; &nbsp; &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; end &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; end

Alex10 · August 21, 2014, 7:41pm

I don’t want to step on Nick, but what you’re asking for seems to be very specific to your own implementation, so unless you explain exactly what you are attempting to achieve, saying “I want a space between each cell” isn’t helping us to help you.

Do you want additional cells to represent the space? Do you just want a specific number of pixels as space between each cell? I’m guessing it’s the later, but without knowing what exactly isn’t working, it’s difficult for us to suggest something does work.

If you could provide more details, images and code explaining what you want to happen and what is happening now, it would help us to help you.

espace3d · August 21, 2014, 7:47pm

hi with this code i make a regular grid with 9 images on 14 separated by a space

local gridGame = {} local row = 9 local cell = 14 local rectx = 30 local recty = 30 local gridscaley = 0.35 local gridscalex = 0.35 local space = 2 local spaceleft =40 local spacetop = 20 local divx=widthscreen/(row\*2) local divy=heightscreen/(cell\*2) &nbsp;&nbsp;&nbsp; for i = 1, cell do &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; gridGame[i] = {}; &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; for k = 1, row do &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; gridGame[i][k] = display.newImage("dalle.png") &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; gridGame[i][k].yScale=0.35 &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; gridGame[i][k].xScale=0.35 &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; gridGame[i][k].alpha = 1 &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; gridGame[i][k].x = (k - 1) \* (rectx + space) + spaceleft &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; gridGame[i][k].y = (i - 1) \* (recty + space) + spacetop &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; &nbsp; &nbsp;&nbsp;&nbsp; end end

but i want to have a non regular grid with for example : empty cells and cells filled

so if could represent my grid with a succesion of 0 and 1 it’ would be easy

0 1 0

1 0 0

1 1 1

have you understand ?

espace3d · August 21, 2014, 7:51pm

i want to do this

nick_sherman · August 21, 2014, 7:55pm

Something like this?

[lua]

local grid = {}

local gridGame = {}

grid[1] = {0, 0, 1, 0}

grid[2] = {1, 0, 1, 1}

grid[3] = {0, 0, 0, 1}

grid[4] = {1, 0, 0, 1}

local row = #grid

local cell = #grid[1]

local rectx = 30

local recty = 30

local gridscaley = 0.35

local gridscalex = 0.35

local space = 2

local spaceleft =40

local spacetop = 20

local divx=widthscreen/(row*2)

local divy=heightscreen/(cell*2)

for i = 1, row do

gridGame[i] = {};

for k = 1, cell do

if grid[i][k] == 1 then

gridGame[i][k] = display.newImage(“dalle.png”)

gridGame[i][k].yScale=0.35

gridGame[i][k].xScale=0.35

gridGame[i][k].alpha = 1

gridGame[i][k].x = (k - 1) * (rectx + space) + spaceleft

gridGame[i][k].y = (i - 1) * (recty + space) + spacetop

else

– cell is blank, do something else

end

[/lua]

Alex10 · August 21, 2014, 7:59pm

To piggyback on Nick’s suggestion, I’d suggest checking out the adapted A* tutorial which has some grid logic built in. I am pointing you to this because it includes information on moving images around a rudimentary “map” which I think would prove useful to you.

espace3d · August 21, 2014, 8:26pm

thank you guys…it’s truly what i’m looking for

espace3d · August 25, 2014, 7:43am

hi,

I have an another question about the use of the grid.

For you what is the best way to have a pseudo infinite grid like the concept of flappy bird ?

put a big number for the row and cell ?

or

make a mini grid and duplicate this grid x number ?

If you have a snippet under the hand it would be cool.

Alex10 · August 25, 2014, 6:16pm

I don’t really ever have a need to generate an infinite grid. If you could give us a bit more detail about what you’re attempting to accomplish, we might be able to suggest some options.

espace3d · August 25, 2014, 6:50pm

i think of something like that with the perspective.lua to move my grid

it is clear that this is a representation because my grid should be even higher

espace3d · August 21, 2014, 2:44pm

anybody ? please

espace3d · August 21, 2014, 3:08pm

i try this but without success

local gridGame = {} local widthscreen =320 local heightscreen =480 local row = 24 local cell = 12 local rectx = 30 local recty = 30 local gridscaley = 0.35 local gridscalex = 0.35 local space = 2 local spaceleft =40 local spacetop = 20 local divx=widthscreen/(row\*2) local divy=heightscreen/(cell\*2) local maze = { &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; { x, x,&nbsp; }, &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; { x, w,&nbsp; }, &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; { x, x,&nbsp; }, &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; { x, w,&nbsp; }, &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; { x, x,&nbsp; }, &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; { x, w,&nbsp; }, &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; { x, w,&nbsp; }, &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; { x, w,&nbsp; }, &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; { x, w,&nbsp; }, &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; { x, w,&nbsp; }, &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; { x, w,&nbsp; }, &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; { x, w,&nbsp; }, &nbsp;&nbsp;&nbsp; } &nbsp;&nbsp;&nbsp; maze.rows = table.getn(maze) &nbsp;&nbsp;&nbsp; maze.columns = table.getn(maze[1]) &nbsp;&nbsp;&nbsp; maze.xStart, maze.yStart = 1, 100 &nbsp;&nbsp;&nbsp; maze.xFinish, maze.yFinish = 24, 7 &nbsp;&nbsp;&nbsp; maze.object = x or w &nbsp;&nbsp;&nbsp;&nbsp; if maze.object == x then &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; image="dalle9.png" &nbsp;&nbsp;&nbsp; end &nbsp;&nbsp;&nbsp; if maze.object == w then &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; image="dalle1.png" &nbsp;&nbsp;&nbsp; end &nbsp; &nbsp; &nbsp;&nbsp;&nbsp; for i = 1, maze.rows do &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; gridGame[i] = {}; &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; for k = 1, maze.columns do &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; gridGame[i][k] = display.newImage(image)&nbsp;&nbsp;&nbsp; &nbsp; &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; gridGame[i][k].yScale=0.35 &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; gridGame[i][k].xScale=0.35 &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; gridGame[i][k].alpha = 1 &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; gridGame[i][k].x = (k - 1) \* (rectx + space) + spaceleft &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; gridGame[i][k].y = (i - 1) \* (recty + space) + spacetop &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; &nbsp; &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; end &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; end

nick_sherman · August 21, 2014, 3:15pm

It’s not really clear what you’re trying to do and what is going wrong…

espace3d · August 21, 2014, 4:48pm

i would simply assign an image to letter x and another image for w.

espace3d · August 21, 2014, 5:54pm

i try an another way but always without success

local widthscreen =320 local heightscreen =480 local space = 2 local rectx = 0.35 local recty = 0.35 local spaceleft =40 local spacetop = 20 local maze = { &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; { 1, 2, 1 }, &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; { 2, 2, 2 }, &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; { 2, 1, 2 }, &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; { 2, 2, 1 }, &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; { 1, 1, 2 }, &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; { 2, 2, 1 }, &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; { 1, 1, 1 }, &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; { 2, 1, 1 }, &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; { 2, 2, 1 }, &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; { 2, 1, 2 }, &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; { 2, 1, 2 }, &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; { 1, 2, 1 }, &nbsp;&nbsp;&nbsp; } &nbsp;&nbsp;&nbsp; maze.rows = table.getn(maze) &nbsp;&nbsp;&nbsp; maze.cells = table.getn(maze[1]) &nbsp;&nbsp; local gridGame = {} &nbsp;&nbsp;&nbsp; for i = 1, maze.rows do &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; gridGame[i] = {}; &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; for k = 1, maze.cells do &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; if gridGame[i][k] == 2 then &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; im = display.newImage("icone.png") &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; end &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; if gridGame[i][k] == 1 then &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; im = display.newImage("bulle2.png") &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; end&nbsp;&nbsp; &nbsp; &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; gridGame[i][k] = im &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; gridGame[i][k].yScale = 0.35 &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; gridGame[i][k].xScale = 0.35 &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; gridGame[i][k].x = (k - 1) \* (rectx + space) + spaceleft &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; gridGame[i][k].y = (i - 1) \* (recty + space) + spacetop &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; &nbsp; &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; end &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; end