Android > Launch App from share with dialog > How to get shared image

Other
#1

Hi,

I want my app do be launched from the android image gallery or whereever a user selects an image and opens the share with dialog.

I already managed that my app will show up in the share with dialog and my app will also launch on that request but how will I get the image that the user wants to share with my app ??

i tried to read the launchArgs but without any success.

Some ideas on that?

thx

here is a code snippet of my main.lua

local function handleLaunch(event)
  if (event and event.url) then
    local url = event.url

    if (string.sub(url, 1, 7) == “file://”) then – handle file
      local alert = native.showAlert( “Got file url”, url, { “OK” })
    else
      local alert = native.showAlert( “Got url”, url, { “OK” })
    end

  end
end

handleLaunch(launchArgs)

#2

launchArgs isn’t an event, it’s just data passed to the app.

Add this to your main.lua:

local json = require("json")local launchArgs = ... print("### --- Launch Arguments ---") print( json.prettify( launchArgs ) )

And see what data is there you can use.

Rob

#3

Hi Rob,

this is what I get:

{

 “androidIntent”:{

   “url”:"",

   “categories”:[],

   “action”:“android.intent.action.SEND”,
   “extras”:"{

    “android.intent.extra.STREAM”:“content://media/external/images/media/48670”,

    “food”:"false,

    “makeup”:"false,

     }

   },

  “url”:""

}

already looks good, but how do I open the image??
I tried photo lib plus to get the image with this photo id (48670) but without success…seems to be a different id.
(btw…photo lib plus is working fine with id’s coming from photoLibPlus.listImages())

thx

Andreas

#4

I assume  you want to display the image using display.newImage() or display.newImageRect()?

If so, you have to use the file IO functions to open the path to the file: /media/external/images/media/48670 in binary mode, read the data in, write it out to system.TemporaryDirectory (or other appropriate sandbox folder) and then you can use display.newImage() to read the file and make a display object out of it.

Rob

#5

hi rob,

yes…you are right, I want to open the image, but the path seems not to be a path to a file or image. As you can see there is no file extension, also this directory structure does not exist on the device. ???

Andreas

#6

After doing a search on the content URL provided, it seems that it’s a stream of data, not a file. Corona SDK isn’t going to have a way to process this data. 

http://stackoverflow.com/questions/20028319/how-to-convert-content-media-external-images-media-y-to-file-storage-sdc

Looking at that post, it’s possible to use Enterprise to convert the URL provided and convert it to a filename. Since you’re an Enterprise customer, I’d consider going this route.

Rob

#7

Dear all, any chance about this ?

I’m developing an app that only need to share a file for BackUp (I can use the social plugging https://coronalabs.com/blog/2015/04/21/tutorial-social-sharing-on-android/

This allow me to send a file to for example Google Drive, or Dropbox,

But, to get external files, I need to read the stream of data.

Any way to do it? Any chance?

Why is so difficult to get content: stream of data?

Any plugging?

Thanks so much all for your excellent job,

#8

launchArgs isn’t an event, it’s just data passed to the app.

Add this to your main.lua:

local json = require("json")local launchArgs = ... print("### --- Launch Arguments ---") print( json.prettify( launchArgs ) )

And see what data is there you can use.

Rob

#9

Hi Rob,

this is what I get:

{

 “androidIntent”:{

   “url”:"",

   “categories”:[],

   “action”:“android.intent.action.SEND”,
   “extras”:"{

    “android.intent.extra.STREAM”:“content://media/external/images/media/48670”,

    “food”:"false,

    “makeup”:"false,

     }

   },

  “url”:""

}

already looks good, but how do I open the image??
I tried photo lib plus to get the image with this photo id (48670) but without success…seems to be a different id.
(btw…photo lib plus is working fine with id’s coming from photoLibPlus.listImages())

thx

Andreas

#10

I assume  you want to display the image using display.newImage() or display.newImageRect()?

If so, you have to use the file IO functions to open the path to the file: /media/external/images/media/48670 in binary mode, read the data in, write it out to system.TemporaryDirectory (or other appropriate sandbox folder) and then you can use display.newImage() to read the file and make a display object out of it.

Rob

#11

hi rob,

yes…you are right, I want to open the image, but the path seems not to be a path to a file or image. As you can see there is no file extension, also this directory structure does not exist on the device. ???

Andreas

#12

After doing a search on the content URL provided, it seems that it’s a stream of data, not a file. Corona SDK isn’t going to have a way to process this data. 

http://stackoverflow.com/questions/20028319/how-to-convert-content-media-external-images-media-y-to-file-storage-sdc

Looking at that post, it’s possible to use Enterprise to convert the URL provided and convert it to a filename. Since you’re an Enterprise customer, I’d consider going this route.

Rob

#13

I’m so glad to introduce you all my new plugin that can manage Uri in Android.

The plugin (actual version) allow to pick a file using the android dialog.

Also allow to get an external file knowing it’s uri.

And can share a file in a simple way.

It is here:

https://marketplace.coronalabs.com/plugin/android-file-and-uri-manager

I’m preparing some samples to show its functionality. For example, with this plugin it is so easy to get a file (custom extension) that it is open with our app.

Hope it can be useful for the community!

Best regards, and thanks for allow me to be here.

#14

Dear all, any chance about this ?

I’m developing an app that only need to share a file for BackUp (I can use the social plugging https://coronalabs.com/blog/2015/04/21/tutorial-social-sharing-on-android/

This allow me to send a file to for example Google Drive, or Dropbox,

But, to get external files, I need to read the stream of data.

Any way to do it? Any chance?

Why is so difficult to get content: stream of data?

Any plugging?

Thanks so much all for your excellent job,

#15

I’m so glad to introduce you all my new plugin that can manage Uri in Android.

The plugin (actual version) allow to pick a file using the android dialog.

Also allow to get an external file knowing it’s uri.

And can share a file in a simple way.

It is here:

https://marketplace.coronalabs.com/plugin/android-file-and-uri-manager

I’m preparing some samples to show its functionality. For example, with this plugin it is so easy to get a file (custom extension) that it is open with our app.

Hope it can be useful for the community!

Best regards, and thanks for allow me to be here.