Is there any way I can encode an image as a string?
I have tried using the following code, but the print statement does not give me a string nearly long enough for an image file:
[lua]path = system.pathForFile(“myfile.jpg”, system.ResourceDirectory)
file = io.open(path, “r”)
image = file:read("*a")
print(image)[/lua]
Well I don’t think you can really print binary data like that. The best way is to get a base64 encoding routine. There is one thats part of the mime package that can be required (local mime = require(“mime”). ) you can google around to find out the calls, its something like b64_encode() or something like that.
There are other base64 encoding libraries that you can find.
Well I don’t think you can really print binary data like that. The best way is to get a base64 encoding routine. There is one thats part of the mime package that can be required (local mime = require(“mime”). ) you can google around to find out the calls, its something like b64_encode() or something like that.
There are other base64 encoding libraries that you can find.
Is there any way I can encode an image as a string?
I have tried using the following code, but the print statement does not give me a string nearly long enough for an image file:
[lua]path = system.pathForFile(“myfile.jpg”, system.ResourceDirectory)
file = io.open(path, “r”)
image = file:read("*a")
print(image)[/lua]
Sorry, are you trying to decode an existed image to bitmap and then re-encode bitmap to image? if yes, I think you can google source code for .NET imaging.
Is there any way I can encode an image as a string?
I have tried using the following code, but the print statement does not give me a string nearly long enough for an image file:
[lua]path = system.pathForFile(“myfile.jpg”, system.ResourceDirectory)
file = io.open(path, “r”)
image = file:read("*a")
print(image)[/lua]
Sorry, are you trying to decode an existed image to bitmap and then re-encode bitmap to image? if yes, I think you can google source code for .NET imaging.