how can I reset my app when exited?

Getting Started Newbie Questions
#1

I want the app to completely reset when the user receives a call or presses the home button or clicks an ad or anything else, so when they user opens the app again it starts over.

local onSystem = function( event )

    if event.type == “applicationStart” then

        print(“start”)

    elseif event.type == “applicationExit” then

        print(“exit”)

    elseif event.type == “applicationSuspend” then

        print(“suspend”)

    elseif event.type == “applicationResume” then

        print(“resume”)

    end

end

 

– setup a system event listener

Runtime:addEventListener( “system”, onSystem )

 

 

 

I have found this but I do not know what to put inside of the applicationSuspend block. Thanks!

#2

You can put 

os.exit()

into your applicationSuspend block and this will force an exit to the OS. However, do read up on the caution (gotchas) on API page : 

http://docs.coronalabs.com/api/library/os/exit.html

#3

oh ok ill be careful

#4

It’s isn’t a matter of being careful.  Apple will reject your app if it just exits.  For Android you should use native.requestExit() instead.

Rob

#5

I found another solution to my problem that did not involve os.exit() Thanks for the heads up though!

#6

You can put 

os.exit()

into your applicationSuspend block and this will force an exit to the OS. However, do read up on the caution (gotchas) on API page : 

http://docs.coronalabs.com/api/library/os/exit.html

#7

oh ok ill be careful

#8

It’s isn’t a matter of being careful.  Apple will reject your app if it just exits.  For Android you should use native.requestExit() instead.

Rob

#9

I found another solution to my problem that did not involve os.exit() Thanks for the heads up though!