I tried using this but it failed.
a = {1,2,3,4,5,6} local function testFunc() for a[1] = 1,6 do --Do something end end
It keeps showing the message ‘=’ or ‘in’ expected near ‘[’ and when I tried using while loop instead, it told me that I compared the number and nil value !? Could anyone help me figure this out or suggest the alternative ways to do things like this?
[lua]
for i = 1, #a, 1 do
print ("Entry “…i…” in table is "…a[i])
end
[/lua]
This will loop through the 6 entries in your ‘a’ table.
Hi Nick, Thank for your reply but I want to use a[1] because I want something like
for i=1,10 do for j=1,10 do for k=1,10 do . . . for p=1,10 do -- Do something end end end end
So, I want to store the iterator in table form because I don’t want to hard code like that. And with that from, it’s easier to read 
This will iterate through the loops depending on the values set in table ‘a’:
[lua]
for i = 1 , a[1], 1 do
for j = 1 , a[2], 1 do
for k = 1 , a[3], 1 do
– do something
end
end
end
[/lua]
If the table values must be the iterator, you could try:
[lua]
repeat
a[1] = a[1] + 1
repeat
a[2] = a[2] + 1
– do something
until a[2] = 10
until a[1] = 6
[/lua]
I haven’t used nested repeat loops before so not sure they behave the same as nested for loops.
How about this …
num\_loops = 3 loop\_vals = {0,0,0} loop\_maxs = {3,3,4} function next\_iter() outp = {} for i = 1,num\_loops do outp[i] = loop\_vals[i] end -- look for sentinel value in last position if( loop\_vals[num\_loops] == (loop\_maxs[num\_loops]+1) ) then return nil end for i = 1,num\_loops do loop\_vals[i] = loop\_vals[i] + 1 if( loop\_vals[i] == loop\_maxs[i] ) then loop\_vals[i] = 0 if( i == num\_loops ) then -- put the sentinel in place for next iter loop\_vals[i] = loop\_maxs[i] + 1 end else -- we're done break end end return outp end while( 1 ) do vals = next\_iter() if( vals == nil ) then break end txt = '' for i=1,num\_loops do txt = txt .. vals[i] .. ',' end print( txt ) end
The output is …
0,0,0, 1,0,0, 2,0,0, 0,1,0, 1,1,0, 2,1,0, 0,2,0, 1,2,0, 2,2,0, 0,0,1, 1,0,1, 2,0,1, 0,1,1, 1,1,1, 2,1,1, 0,2,1, 1,2,1, 2,2,1, 0,0,2, 1,0,2, 2,0,2, 0,1,2, 1,1,2, 2,1,2, 0,2,2, 1,2,2, 2,2,2, 0,0,3, 1,0,3, 2,0,3, 0,1,3, 1,1,3, 2,1,3, 0,2,3, 1,2,3, 2,2,3,
(it starts counting with 0 up to n-1, you might need to adjust the sentinel value if you want 1 to n instead)
Thank you very much Nick and jbp1, I’ve successfully done this task finally. 
[lua]
for i = 1, #a, 1 do
print ("Entry “…i…” in table is "…a[i])
end
[/lua]
This will loop through the 6 entries in your ‘a’ table.
Hi Nick, Thank for your reply but I want to use a[1] because I want something like
for i=1,10 do for j=1,10 do for k=1,10 do . . . for p=1,10 do -- Do something end end end end
So, I want to store the iterator in table form because I don’t want to hard code like that. And with that from, it’s easier to read
This will iterate through the loops depending on the values set in table ‘a’:
[lua]
for i = 1 , a[1], 1 do
for j = 1 , a[2], 1 do
for k = 1 , a[3], 1 do
– do something
end
end
end
[/lua]
If the table values must be the iterator, you could try:
[lua]
repeat
a[1] = a[1] + 1
repeat
a[2] = a[2] + 1
– do something
until a[2] = 10
until a[1] = 6
[/lua]
I haven’t used nested repeat loops before so not sure they behave the same as nested for loops.
How about this …
num\_loops = 3 loop\_vals = {0,0,0} loop\_maxs = {3,3,4} function next\_iter() outp = {} for i = 1,num\_loops do outp[i] = loop\_vals[i] end -- look for sentinel value in last position if( loop\_vals[num\_loops] == (loop\_maxs[num\_loops]+1) ) then return nil end for i = 1,num\_loops do loop\_vals[i] = loop\_vals[i] + 1 if( loop\_vals[i] == loop\_maxs[i] ) then loop\_vals[i] = 0 if( i == num\_loops ) then -- put the sentinel in place for next iter loop\_vals[i] = loop\_maxs[i] + 1 end else -- we're done break end end return outp end while( 1 ) do vals = next\_iter() if( vals == nil ) then break end txt = '' for i=1,num\_loops do txt = txt .. vals[i] .. ',' end print( txt ) end
The output is …
0,0,0, 1,0,0, 2,0,0, 0,1,0, 1,1,0, 2,1,0, 0,2,0, 1,2,0, 2,2,0, 0,0,1, 1,0,1, 2,0,1, 0,1,1, 1,1,1, 2,1,1, 0,2,1, 1,2,1, 2,2,1, 0,0,2, 1,0,2, 2,0,2, 0,1,2, 1,1,2, 2,1,2, 0,2,2, 1,2,2, 2,2,2, 0,0,3, 1,0,3, 2,0,3, 0,1,3, 1,1,3, 2,1,3, 0,2,3, 1,2,3, 2,2,3,
(it starts counting with 0 up to n-1, you might need to adjust the sentinel value if you want 1 to n instead)
Thank you very much Nick and jbp1, I’ve successfully done this task finally.