Hello
I have this mini quiz game were there is 10 short questions. Ok what I need help is I want to the quiz to go through 10 scenes but without repeating So after going through 10 scenes it then switches to the results.
Example: Scene2, Scene5, Scene 10, Scene1, Scene3, Scene9, Scene8, Scene4, Scene6, Scene7 then Results.lua
Anyone know how this attempt is done? [import]uid: 17058 topic_id: 33069 reply_id: 333069[/import]
Hi.
I think somebody posted shuffling code before, so there may be something better than this. Otherwise, the following should be about right:
[lua]local indices = {}
local order = {}
– Initial indices, all in order
for i = 1, 10 do
indices[i] = i
end
for n = 10, 1, -1 do – Iterate backwards because we’re removing elements
local slot = math.random(n) – Choose random slot from 1 to n
order[#order + 1] = indices[slot]
indices[slot] = indices[n] – Backfill the used-up slot so we don’t have to move elements down
end
– Now use ‘order’ to look up your scenes…[/lua] [import]uid: 27791 topic_id: 33069 reply_id: 131339[/import]
What do I put here director:changeScene() when switching scenes? [import]uid: 17058 topic_id: 33069 reply_id: 131341[/import]
Unless you need to do very specific things for each question, I would recommend you package the questions together in one scene. If you need to make a change you’ll have to go through all 10 scenes to do it, and you are probably redoing a bunch of stuff.
I could be wrong though, really depends on what you’re doing in the app.
[import]uid: 181948 topic_id: 33069 reply_id: 131356[/import]
Hi.
I think somebody posted shuffling code before, so there may be something better than this. Otherwise, the following should be about right:
[lua]local indices = {}
local order = {}
– Initial indices, all in order
for i = 1, 10 do
indices[i] = i
end
for n = 10, 1, -1 do – Iterate backwards because we’re removing elements
local slot = math.random(n) – Choose random slot from 1 to n
order[#order + 1] = indices[slot]
indices[slot] = indices[n] – Backfill the used-up slot so we don’t have to move elements down
end
– Now use ‘order’ to look up your scenes…[/lua] [import]uid: 27791 topic_id: 33069 reply_id: 131339[/import]
What do I put here director:changeScene() when switching scenes? [import]uid: 17058 topic_id: 33069 reply_id: 131341[/import]
Yes, what you want to do is “shuffle” the scene names.
Create a table that has the various scene names in it:
local sceneNames = {"scene1", "scene2", "scene3", "scene4"}
Then call this function:
local function shuffle(t) local iterations = #t local j for i = iterations, 2, -1 do j = math.random(i) t[i], t[j] = t[j], t[i] end end shuffle(sceneNames)
after that the scenes are randomized, no repeats.
[import]uid: 19626 topic_id: 33069 reply_id: 131388[/import]
Unless you need to do very specific things for each question, I would recommend you package the questions together in one scene. If you need to make a change you’ll have to go through all 10 scenes to do it, and you are probably redoing a bunch of stuff.
I could be wrong though, really depends on what you’re doing in the app.
[import]uid: 181948 topic_id: 33069 reply_id: 131356[/import]
Yes, what you want to do is “shuffle” the scene names.
Create a table that has the various scene names in it:
local sceneNames = {"scene1", "scene2", "scene3", "scene4"}
Then call this function:
local function shuffle(t) local iterations = #t local j for i = iterations, 2, -1 do j = math.random(i) t[i], t[j] = t[j], t[i] end end shuffle(sceneNames)
after that the scenes are randomized, no repeats.
[import]uid: 19626 topic_id: 33069 reply_id: 131388[/import]
Hi Rob,
i tried your function to randomize numbers from 1 to 3 without repetition but I was getting repeated numbers: The code is below
[lua]
for i=1, 3 do
postable[i]=math.random(3)
end
local function shuffle(t)
local iterations = #t
local j
for i = iterations,2, -1 do
j = math.random(i)
t[i], t[j] = t[j], t[i]
end
end
shuffle(postable)
for i = 1 , (#postable) do
print(postable[i] )
end
[/lua]
can you please advice ?
Hi @alzaabi980,
Usually it helps to “seed” the random number generator, like shown here:
http://docs.coronalabs.com/api/library/math/randomseed.html
Hope this helps,
Brent Sorrentino
Hi.
You probably don’t want
for i=1, 3 do postable[i]=math.random(3) end
since math.random() may return the same number twice (or thrice, etc.). Rather, just populate your table as
for i=1, 3 do postable[i]=i end
That way you know you have a well-formed table. Then just shuffle that.
I generally do my strict randoms like so. Not sure if it’s the perfect way though…
[lua]
–< Seed random
math.randomseed( os.time() )
–< Localize math.random
local mRan = math.random
–< Create the base table
local baseTable = { “scene1”, “scene2”, “scene3”, “scene4”, “scene5” }
–< Init final mixed table
local mixedTable = {}
–< Do work
for i=#baseTable, 1, -1 do
--< Get a random position
local tmpRan = mRan( #baseTable )
--< Get the table value at position
local tblVal = baseTable[tmpRan]
--< Insert value in mixedTable
table.insert( mixedTable, tblVal )
--< Remove value from base table, to stop duplicates
table.remove( baseTable, tmpRan )
end
–< Print out mixedTable
for j=1, #mixedTable do
print( mixedTable[j] )
end
[/lua]
And if you want to add the results…
[lua]table.insert( mixedTable, “results.lua” )[/lua]
But it would probably be better to just look for the end of your scene table and deal with it then.
Cheers.
Hi Rob,
i tried your function to randomize numbers from 1 to 3 without repetition but I was getting repeated numbers: The code is below
[lua]
for i=1, 3 do
postable[i]=math.random(3)
end
local function shuffle(t)
local iterations = #t
local j
for i = iterations,2, -1 do
j = math.random(i)
t[i], t[j] = t[j], t[i]
end
end
shuffle(postable)
for i = 1 , (#postable) do
print(postable[i] )
end
[/lua]
can you please advice ?
Hi @alzaabi980,
Usually it helps to “seed” the random number generator, like shown here:
http://docs.coronalabs.com/api/library/math/randomseed.html
Hope this helps,
Brent Sorrentino
Hi.
You probably don’t want
for i=1, 3 do postable[i]=math.random(3) end
since math.random() may return the same number twice (or thrice, etc.). Rather, just populate your table as
for i=1, 3 do postable[i]=i end
That way you know you have a well-formed table. Then just shuffle that.
I generally do my strict randoms like so. Not sure if it’s the perfect way though…
[lua]
–< Seed random
math.randomseed( os.time() )
–< Localize math.random
local mRan = math.random
–< Create the base table
local baseTable = { “scene1”, “scene2”, “scene3”, “scene4”, “scene5” }
–< Init final mixed table
local mixedTable = {}
–< Do work
for i=#baseTable, 1, -1 do
--< Get a random position
local tmpRan = mRan( #baseTable )
--< Get the table value at position
local tblVal = baseTable[tmpRan]
--< Insert value in mixedTable
table.insert( mixedTable, tblVal )
--< Remove value from base table, to stop duplicates
table.remove( baseTable, tmpRan )
end
–< Print out mixedTable
for j=1, #mixedTable do
print( mixedTable[j] )
end
[/lua]
And if you want to add the results…
[lua]table.insert( mixedTable, “results.lua” )[/lua]
But it would probably be better to just look for the end of your scene table and deal with it then.
Cheers.
Thanks Brent and StarCrunch ,
I did what you both recommended and finally I get the random function works without repeated values.
I appreciate your help
Abdul
Thanks Brent and StarCrunch ,
I did what you both recommended and finally I get the random function works without repeated values.
I appreciate your help
Abdul