If number reaches every 100 - code?

Hi

This should be a simple one but I cant seem to find the answer.

Rather than doing:

if numberOfLives == 33 then
n = n + 1

elseif numberOfLives == 66 then
n = n + 1

elseif numberOfLives == 99 then
n = n + 1


Is there a way to make it know something like:

elseif numberOfLives == (every 33 times) then
n = n + 1

This would save me lines of code

Im sure Im missing something so obvious

please help [import]uid: 43191 topic_id: 7782 reply_id: 307782[/import]

your code doesnt match your subject question. what are you trying to do?

[lua]for numberOfLives=0, 200, 1 do
if(numberOfLives%33==0) then
print(numberOfLives)
end
end[/lua] [import]uid: 6645 topic_id: 7782 reply_id: 27607[/import]

Hi thanks sorry was 3am here !

I meant every 33 times. So if number of lives hit every 33 times [import]uid: 43191 topic_id: 7782 reply_id: 27626[/import]

got it , the %33 was it ! [import]uid: 43191 topic_id: 7782 reply_id: 27630[/import]