keep track of time app is open?

Getting Started Newbie Questions
#1

Hi, I’d like to show ad to the user every 10 minutes, but it should be after 10 minutes of playing in game, not 1 minute playing and 9 minutes application in background :wink:

How would you do that? 

#2

I would use timer.

Example

local showAdsTimer local function onTimer( event )   -- Show Ads now   print( 'Your Ads' ) end -- 10 000 ms == 10 seconds showAdsTimer = timer.performWithDelay( 10000, onTimer, 0 ) -- Whatever you need you can pause or resume timer  timer.pause( showAdsTimer ) timer.resume( showAdsTimer ) -- When you don't need timer more you have to remove it timer.cancel( showAdsTimer  )

ldurniat

#3

To add to what @ldurniat suggested, the reason system timer is the way to go is because it sleeps when the apps sleeps.  So, sleeping won’t affect the ‘actually playing time’ measurement.

Note: timer.peformWithDelay() uses the system timer.

#4

I would use timer.

Example

local showAdsTimer local function onTimer( event )   -- Show Ads now   print( 'Your Ads' ) end -- 10 000 ms == 10 seconds showAdsTimer = timer.performWithDelay( 10000, onTimer, 0 ) -- Whatever you need you can pause or resume timer  timer.pause( showAdsTimer ) timer.resume( showAdsTimer ) -- When you don't need timer more you have to remove it timer.cancel( showAdsTimer  )

ldurniat

#5

To add to what @ldurniat suggested, the reason system timer is the way to go is because it sleeps when the apps sleeps.  So, sleeping won’t affect the ‘actually playing time’ measurement.

Note: timer.peformWithDelay() uses the system timer.