Not able to upload Zip file on server

bahshat · April 27, 2016, 12:48pm

Tries so many ways but couldn’t upload zip file on server.

Please help me to sort it.

local url = "http://192.168.0.110/souqhero/Mobile/pos" local method = "POST" ------------------------------------------------------------------------------------ local function uploadListener( event ) &nbsp; &nbsp; if ( event.isError ) then &nbsp; &nbsp; &nbsp; &nbsp;&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; print( "Network Error." ) &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; else &nbsp; &nbsp; &nbsp; &nbsp; if ( event.phase == "began" ) then &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; print( "Upload started" ) &nbsp; &nbsp; &nbsp; &nbsp; elseif ( event.phase == "progress" ) then &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; print( "Uploading... bytes transferred ", event.bytesTransferred ) &nbsp; &nbsp; &nbsp; &nbsp; elseif ( event.phase == "ended" ) then &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; print( "Upload ended..." ) &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; print( "Status:", event.status ) &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; print( "Response:", event.response ) &nbsp; &nbsp; &nbsp; &nbsp; end &nbsp; &nbsp; end end ------------------------------------------------------------------------------------ local params = { &nbsp; &nbsp; timeout = 60, &nbsp; &nbsp; progress = true, &nbsp; &nbsp; bodyType = "binary" } ------------------------------------------------------------------------------------ local baseDirectory = system.DocumentsDirectory local contentType = "application/zip" &nbsp; ------------------------------------------------------------------------------------ local headers =&nbsp; { &nbsp; &nbsp; name = "newRequest.zip" } headers["Content-Type"]=contentType params.headers=headers network.upload( url , method, uploadListener, params, "newRequest.zip", baseDirectory, contentType )

rob · April 27, 2016, 6:15pm

network.upload() is using “PUT” not “POST” as how it transfers the file. Your receiving script needs to know how to handle this. If you need to use POST, then you will probably want to use network.request() instead and configure the header and body paramters in the options table correctly. See:

https://coronalabs.com/blog/2014/02/25/tutorial-uploading-files-demystified/

Rob

rob · April 27, 2016, 6:15pm

network.upload() is using “PUT” not “POST” as how it transfers the file. Your receiving script needs to know how to handle this. If you need to use POST, then you will probably want to use network.request() instead and configure the header and body paramters in the options table correctly. See:

https://coronalabs.com/blog/2014/02/25/tutorial-uploading-files-demystified/

Rob