perform a function randomly from a set/group of functions?

Getting Started Newbie Questions
#1

I have a beat em up game and i want my enemy to spawn random items when it’s killed.

for example i have spawnCoin as a function and spawnHealthitem spawnArmouritem etc. and i want each enemy to drop say 2 coins and a health one time or 4 coins and a armour another or just some coins one time.

I know there is a probably a real simple way to do this (probably using math.random somehow?) but can’t get my head around it so any help would be much appreciated!

Regards,

Finn M.

#2 
function spawnA()   print("A") end function spawnB()   print("B") end function spawnRandomStuff()   local spawnFunctions = {spawnA, spawnB}   for \_ = 1, 5 do     spawnFunctions[math.random(#spawnFunctions)]()   end end spawnRandomStuff()  
#3

that’s great thanks a lot for the quick reply!

#4

some other options

local spawn ={} spawn[1]=function() --spawn1 end spawn[2]=function() --spawn2 end local function spawnObject() for a =1,5 do spawn[math.random(1,2)]() end spawnObject()

or

local objects ={"obj1.png","obj2.png"} local function spawn() for a=1,5 do obj= display.newImage( objects[math.random(1,#objects)], ............) end end spawn()
#5 
function spawnA()   print("A") end function spawnB()   print("B") end function spawnRandomStuff()   local spawnFunctions = {spawnA, spawnB}   for \_ = 1, 5 do     spawnFunctions[math.random(#spawnFunctions)]()   end end spawnRandomStuff()  
#6

that’s great thanks a lot for the quick reply!

#7

some other options

local spawn ={} spawn[1]=function() --spawn1 end spawn[2]=function() --spawn2 end local function spawnObject() for a =1,5 do spawn[math.random(1,2)]() end spawnObject()

or

local objects ={"obj1.png","obj2.png"} local function spawn() for a=1,5 do obj= display.newImage( objects[math.random(1,#objects)], ............) end end spawn()