Simplify "if" construction

baks2711 · May 24, 2013, 6:37pm

Hello. I make a counter and use operator “if”

It works but its very huge.

How i can simplify this construction?

man.countboomerangs = 15 man.countboomerangs = man.countboomerangs - 1 local killedcounter = { "0","1","2","3","4","5","6","7","8","9","10"} &nbsp;killedcounter[1] = "images/0.png" &nbsp;killedcounter[2] = "images/1.png" &nbsp;killedcounter[3] = "images/2.png" &nbsp;killedcounter[4] = "images/3.png" &nbsp;killedcounter[5] = "images/4.png" &nbsp;killedcounter[6] = "images/5.png" &nbsp;killedcounter[7] = "images/6.png" &nbsp;killedcounter[8] = "images/7.png" &nbsp;killedcounter[9] = "images/8.png" &nbsp;killedcounter[10] = "images/9.png" &nbsp; &nbsp; &nbsp; if man.countboomerangs == 14 &nbsp;then&nbsp; &nbsp; &nbsp; &nbsp; kilcounter1 = display.newImage(killedcounter[2],70,30) &nbsp; &nbsp; &nbsp; kilcounter2 = display.newImage(killedcounter[5],110,30) &nbsp; &nbsp; &nbsp; elseif man.countboomerangs == 13 then&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; kilcounter1:removeSelf() &nbsp; &nbsp; &nbsp; &nbsp; kilcounter2:removeSelf() &nbsp; &nbsp; &nbsp; &nbsp; kilcounter3 = display.newImage(killedcounter[2],70,30) &nbsp; &nbsp; &nbsp; &nbsp; kilcounter4 = display.newImage(killedcounter[4],110,30) &nbsp; &nbsp; &nbsp; elseif man.countboomerangs == 12 then&nbsp;... &nbsp;