sorry but how do you this ? too difficult to discribe

[bexphones]

hi everybody but i can’t do my function returnTheNumberOfTheLevel(currentlevel)

this works  returnTheNumberOfTheLevel(1) but i want this returnTheNumberOfTheLevel(currentlevel)

What’s the solution and why doesn’t it work?

thanks

--LEVEL local level = {} level[1] = {} level[1].playersbegin = 2 level[1].playermax = 3 level[1].time = 60 level[1].textLevelPrecision = "funny Level" level[1].countTap = 4 level[1].Background = "back01.png" level[1].difficulty = 0.25 --to 0.9 more difficult level[1].special = 0 level[2] = {} level[2].playersbegin = 8 level[2].playermax = 3 level[2].time = 60 level[2].textLevelPrecision = "level de fou" level[2].countTap = 1 level[2].Background = "back02.png" level[2].difficulty = 0.3  --to 0.9 more difficult level[2].special = 0 local textNumberLevel = display.newText(myGrouptext, "", 100,100, fontLuckiest, 25) textNumberLevel:setFillColor(1,1,1) textNumberLevel.text = 1 textNumberLevel.anchorX = 0 local currentLevel = print(textNumberLevel.text) local function returnTheNumberOfTheLevel(d) b = level[d].time c = level[d].textLevelPrecision difficulty = level[d].difficulty e = level[d].special countTap = level[d].countTap imageBackground = level[d].Background playersbegin = level[d].playersbegin playermax = level[d].playermax textLevelPrecision.transition = transition.to(textLevelPrecision,{alpha = 0,time=700,transition= easing.inOutBounce, delay=2000} ) textLevelText.transition = transition.to(textLevelText,{alpha = 0,time=700,transition= easing.inOutBounce, delay=2000} ) return b,c,e,countTap, playersbegin, imageBackground, playermax, difficulty end returnTheNumberOfTheLevel(currentlevel)

[Stephen_Lewis]

You are setting the variable “currentLevel” =  to a print text function, rather than to a number.

Also, you are using an undefined variable “currentlevel” when you call the function returnTheNumberOfTheLevel.  You probably meant to use “currentLevel”.  Those are two different variables since one uses the capital L.

[bexphones]

hi Stephen Lewis,

for the capital is a typo. in my snippet it’s alright 

returnTheNumberOfTheLevel(currentLevel)

i have tried this but it’s don’t worked :

local currentLevel = textNumberLevel.text

while

print("currentLevel", currentLevel)

return

currentLevel 1

any suggestions ?

[Stephen_Lewis]

It looks like what you are trying to do is set the text string parameter of a display.newText object to be the number 1.    

textNumberLevel.text = 1

But you can’t do that.  The .text parameter of a newText object is supposed to be a string, so setting it to 1 is actually setting it to “1”.  (The string “1”, not the number 1).   Lua has a fancy trick of automatically converting a number to a string if it is expecting a string.  

You can check that by printing the type of the variable using a line like:

print(type(currentLevel))

I’m guessing it will print “string” instead of “number”.

So you are trying to access your table entry at index number 1 using the string “1” which you have not defined.  

A simple fix would be to convert the string to a number when you call your function, like this:

returnTheNumberOfTheLevel(tonumber(currentLevel))

[bexphones]

Thanks Stephen Lewis,

Now i know the difference between the string and the number.

II changed my code to avoid this ambiguity and have only numbers. Thank you again for this learning and good day

[Stephen_Lewis]

You are setting the variable “currentLevel” =  to a print text function, rather than to a number.

Also, you are using an undefined variable “currentlevel” when you call the function returnTheNumberOfTheLevel.  You probably meant to use “currentLevel”.  Those are two different variables since one uses the capital L.

[bexphones]

hi Stephen Lewis,

for the capital is a typo. in my snippet it’s alright 

returnTheNumberOfTheLevel(currentLevel)

i have tried this but it’s don’t worked :

local currentLevel = textNumberLevel.text

while

print("currentLevel", currentLevel)

return

currentLevel 1

any suggestions ?

[Stephen_Lewis]

It looks like what you are trying to do is set the text string parameter of a display.newText object to be the number 1.    

textNumberLevel.text = 1

But you can’t do that.  The .text parameter of a newText object is supposed to be a string, so setting it to 1 is actually setting it to “1”.  (The string “1”, not the number 1).   Lua has a fancy trick of automatically converting a number to a string if it is expecting a string.  

You can check that by printing the type of the variable using a line like:

print(type(currentLevel))

I’m guessing it will print “string” instead of “number”.

So you are trying to access your table entry at index number 1 using the string “1” which you have not defined.  

A simple fix would be to convert the string to a number when you call your function, like this:

returnTheNumberOfTheLevel(tonumber(currentLevel))

[bexphones]

Thanks Stephen Lewis,

Now i know the difference between the string and the number.

II changed my code to avoid this ambiguity and have only numbers. Thank you again for this learning and good day