Threshold detection help

Getting Started Newbie Questions
#1

In my app there are three thresholds each with a different multiplier assigned to it.

So when you shoot the bullet depending on where the balloon is popped, that is what the score will be multiplied by. 

Code for thresholds:

thresholds[1]=display.newRect(0,0,768,200) --This is the region with 5x multiplier    thresholds[2]=display.newRect(0,0,768,60)  --This is the region with 10x multiplier    thresholds[3]=display.newRect(0,0,768,260) --This is the region with 1x multiplier    thresholds[1]:setFillColor(math.random(0, 255)/255, math.random(0, 255)/255, math.random(0, 255)/255)    thresholds[2]:setFillColor(math.random(0, 255)/255, math.random(0, 255)/255, math.random(0, 255)/255)    thresholds[3]:setFillColor(math.random(0, 255)/255, math.random(0, 255)/255, math.random(0, 255)/255)    thresholds[1].x=\_W/2    thresholds[1].y=\_H-(thresholds[1].height+112)    thresholds[2].x=\_W/2    thresholds[2].y=(\_H-thresholds[1].height-243)    thresholds[3].x=\_W/2    thresholds[3].y=\_H+(thresholds[3].height\*.5-210)    txt1=display.newText("1x",500, 500, native.systemFontBold, 30 )        txt1.x=\_W-50        txt1.y=\_H-150    txt2=display.newText("5x",100, 200, native.systemFontBold, 30 )        txt2.x=\_W-50        txt2.y=\_H-350    txt3=display.newText("10x",100, 200, native.systemFontBold, 30 )        txt3.x=\_W-50        txt3.y=\_H-452

To assign the multiplier for each threshold i do this:

 for i=1,#thresholds do     thresholds[i].boundary=math.ceil(thresholds[i].y+(thresholds[i].height\*.5))                   if (i==3) then         thresholds[i].multiplier=1         elseif (i==2) then          thresholds[i].multiplier=10         else         thresholds[i].multiplier=5          end      end

The multiplier for my 3rd and 1st threshold (so the 1x and 5x multiplier) work but when i pop a balloon in the x10 region/threshold[2] the multiplier is 1 not 10. Why is this?

#2

Debugging this seems not especially worthwhile. Why don’t you simply assign the multiplier values when you are creating the threshold objects?

#3

That doesn’t work due to my other code for the balloons which check the thresholds.boundary property in order to assign the value. That is why i included the boundary checking vs, just regularly assigning a multiplier. Do you know any other solutions because that doesn’t work.

#4

Could you not just assign the multiplier based on the Y position of the balloon?

Quick (unchecked) example…

if balloon.y \< foo then -- foo = bottom edge of top area multiplier = 10 else if balloon.y \> foo2 then -- foo2 = bottom edge of middle area multiplier = 1 else multiplier = 5 end
#5

I cannot do anything that omits the boundaries. Here is why, this is the code for how I make the balloon check which threshold it is in.

local function checkThreshold(obj1,obj2 ) &nbsp; &nbsp;if (obj1 and obj2) then &nbsp; &nbsp; &nbsp; if(obj1.y\<obj2[1].boundary and obj1.y \> obj2[2].boundary) then &nbsp; &nbsp; &nbsp; if (obj1.multiplier==nil) then &nbsp; &nbsp; &nbsp; end &nbsp; &nbsp; &nbsp; obj1.multiplier=obj2[1].multiplier&nbsp; &nbsp; &nbsp; &nbsp; elseif(obj1.y\<obj2[2].boundary and obj1.y\>obj2[3].boundary) then &nbsp; &nbsp; &nbsp; if(obj1.multiplier==obj2[1].multiplier) then &nbsp; &nbsp; &nbsp; obj1:flash() &nbsp; &nbsp; &nbsp; end &nbsp; &nbsp; &nbsp; &nbsp; obj1.multiplier=obj2[2].multiplier &nbsp; &nbsp; &nbsp; elseif(obj1.y\<obj2[3].boundary and obj1.y\>-10) then &nbsp; &nbsp; &nbsp; &nbsp; if(obj1.multiplier==obj2[2].multiplier) then &nbsp; &nbsp; &nbsp; &nbsp; obj1:flash() &nbsp; &nbsp; &nbsp; &nbsp; end &nbsp; &nbsp; &nbsp; &nbsp; obj1.multiplier=obj2[3].multiplier &nbsp; &nbsp; &nbsp; &nbsp; elseif(obj1.y\<-10) then &nbsp; &nbsp; &nbsp; &nbsp; if(obj1.timer) then &nbsp; &nbsp; &nbsp; &nbsp; obj1:pop() &nbsp; &nbsp; &nbsp; &nbsp; end &nbsp; &nbsp; &nbsp; &nbsp; end &nbsp; &nbsp; &nbsp;end end
#6

Debugging this seems not especially worthwhile. Why don’t you simply assign the multiplier values when you are creating the threshold objects?

#7

That doesn’t work due to my other code for the balloons which check the thresholds.boundary property in order to assign the value. That is why i included the boundary checking vs, just regularly assigning a multiplier. Do you know any other solutions because that doesn’t work.

#8

Could you not just assign the multiplier based on the Y position of the balloon?

Quick (unchecked) example…

if balloon.y \< foo then -- foo = bottom edge of top area multiplier = 10 else if balloon.y \> foo2 then -- foo2 = bottom edge of middle area multiplier = 1 else multiplier = 5 end
#9

I cannot do anything that omits the boundaries. Here is why, this is the code for how I make the balloon check which threshold it is in.

local function checkThreshold(obj1,obj2 ) &nbsp; &nbsp;if (obj1 and obj2) then &nbsp; &nbsp; &nbsp; if(obj1.y\<obj2[1].boundary and obj1.y \> obj2[2].boundary) then &nbsp; &nbsp; &nbsp; if (obj1.multiplier==nil) then &nbsp; &nbsp; &nbsp; end &nbsp; &nbsp; &nbsp; obj1.multiplier=obj2[1].multiplier&nbsp; &nbsp; &nbsp; &nbsp; elseif(obj1.y\<obj2[2].boundary and obj1.y\>obj2[3].boundary) then &nbsp; &nbsp; &nbsp; if(obj1.multiplier==obj2[1].multiplier) then &nbsp; &nbsp; &nbsp; obj1:flash() &nbsp; &nbsp; &nbsp; end &nbsp; &nbsp; &nbsp; &nbsp; obj1.multiplier=obj2[2].multiplier &nbsp; &nbsp; &nbsp; elseif(obj1.y\<obj2[3].boundary and obj1.y\>-10) then &nbsp; &nbsp; &nbsp; &nbsp; if(obj1.multiplier==obj2[2].multiplier) then &nbsp; &nbsp; &nbsp; &nbsp; obj1:flash() &nbsp; &nbsp; &nbsp; &nbsp; end &nbsp; &nbsp; &nbsp; &nbsp; obj1.multiplier=obj2[3].multiplier &nbsp; &nbsp; &nbsp; &nbsp; elseif(obj1.y\<-10) then &nbsp; &nbsp; &nbsp; &nbsp; if(obj1.timer) then &nbsp; &nbsp; &nbsp; &nbsp; obj1:pop() &nbsp; &nbsp; &nbsp; &nbsp; end &nbsp; &nbsp; &nbsp; &nbsp; end &nbsp; &nbsp; &nbsp;end end