here is a simple table
tableForImages = {} for c = 1, 10 do tableForImages[c] = "hello" tableForImages[c].status = "hi" end
here is the error string:
attempt to index field ‘?’ (a string value)
here is a simple table
tableForImages = {} for c = 1, 10 do tableForImages[c] = "hello" tableForImages[c].status = "hi" end
here is the error string:
attempt to index field ‘?’ (a string value)
In the line **tableForImages[c] = “hello” **you make tableForImages[c] a string, “hello”.
Then in the next line you are trying to treat this string as a table. So you need to change it up a bit.
Like this for example:
[lua]
tableForImages = {}
for c = 1, 10 do
tableForImages[c] = {}
tableForImages[c].something = “hello”
tableForImages[c].status = “hi”
end
[/lua]
Oh I see, thanks 
btw, If I use it like this
testImage[i] = display.newImage("whateverimage.png, params) testImage[i].status = "Open Me"
it works, or whatever display object I use
That’s because display.newImage() returns a table, which is similar to Jon’s setting it to an empty table with his " = {} " assignment.
Rob
Oh okay thanks
In the line **tableForImages[c] = “hello” **you make tableForImages[c] a string, “hello”.
Then in the next line you are trying to treat this string as a table. So you need to change it up a bit.
Like this for example:
[lua]
tableForImages = {}
for c = 1, 10 do
tableForImages[c] = {}
tableForImages[c].something = “hello”
tableForImages[c].status = “hi”
end
[/lua]
Oh I see, thanks 
btw, If I use it like this
testImage[i] = display.newImage("whateverimage.png, params) testImage[i].status = "Open Me"
it works, or whatever display object I use
That’s because display.newImage() returns a table, which is similar to Jon’s setting it to an empty table with his " = {} " assignment.
Rob
Oh okay thanks